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Variable

Variable

Search complete. 31 mentions across 3 episodes found for "Variable".

Oct 8, 2026

Randy MelyGUEST
5:22
Yeah, absolutely.
Randy MelyGUEST
5:24
I think you can make it a little bit more simpler at the genesis of the question by just asking yourself one question before you actually fire off that request to the HRBP or whoever, and that is, if X, I will do A.
Randy MelyGUEST
5:36
If Z, I will do B.
Randy MelyGUEST
5:39
Basically, what are you deciding you're going to do depending on what the data shows you? That's the first thing you need to ask yourself as the person firing off that request, because that changes-
Randy MelyGUEST
5:47
the whole conversation.
Randy MelyGUEST
5:49
So going back to that example where I was talking about, you know, I feel like the sales team.
Randy MelyGUEST
5:52
So you might say, if attrition in these critical roles is at X, I will start funding a retention program or looking into a retention program.
Randy MelyGUEST
6:01
If it's Y, I'll do nothing.
Michael RussellHOST
6:34
We're gonna have the average, which is sixty-nine point seven two three, equals the mass of the first one, sixty-eight whatever, times its percentage.
Michael RussellHOST
6:44
So X here is gonna be the percentage of the sixty-nine, and we're gonna add it to the mass of the second one, that seventy point nine number, times the abundance of the other one, which we'll call Y.
Michael RussellHOST
6:56
So you can see right now we have two unknowns, X and Y, and those are the two percentages, uh, of the gallium-61 and gallium-71, and those are tough to solve.
Michael RussellHOST
7:08
However, the two abundances together have to equal a hundred percent, or if you're talking about them in, not-- in decimal version, one, which is a hundred percent in decimal, one equals X plus Y.
Michael RussellHOST
7:21
So what you can do then is have one of them, we'll say Y, equals one minus X.
Michael RussellHOST
7:28
If you subtract X from both sides on that last one, you get Y equals one minus X, and you're good to go.
Michael RussellHOST
7:35
So what we're gonna do in a little bit is we're gonna substitute this part right here, the one minus X, we're gonna substitute it up here.
Michael RussellHOST
7:44
Then we're gonna have one equation with one unknown X, and you can solve for X, and at the very end, go back and go one minus X to solve for Y.
Ted PavlicHOST
9:59
You can run that into the inverse of the CDF.
Ted PavlicHOST
10:03
So on the homework, as we'll see today as well, you just set this thing equal to R and then solve for X in terms of R.
Ted PavlicHOST
10:13
And then that will give you your inverse sampling, your inverse sampler, inverse transform sampler.
Ted PavlicHOST
10:19
And that's just equivalent to taking numbers and running them in the Y-axis.

47 MINS LATER

Ted PavlicHOST
57:37
You solve for the inverse of that.
Ted PavlicHOST
57:40
So you set R equal to the CDF that you have, and then you invert it.
Ted PavlicHOST
57:45
So you solve for X in terms of R.
Ted PavlicHOST
57:48
And hopefully you can do that.

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